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Answer (Detailed Solution Below)

Option 4 : 8

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Detailed Solution

सही उत्तर 8 है।

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PrepSnapprepsnap.in • Part -A

Question:

How many distinct states does a 4-bit Johnson (twisted-ring) counter cycle through before repeating? / 4-बिट Johnson (twisted-ring) counter दोहराने से पहले कितनी भिन्न अवस्थाओं से गुज़रता है?

1.
16
2.
4
3.
6
4.
8

Correct Answer: 8

A Johnson counter with n flip-flops has 2n states, so 2 × 4 = 8. (A 4-bit ring counter would have only 4, and 16 is the trap for a full binary counter.) / n फ्लिप-फ्लॉप वाले Johnson counter में 2n अवस्थाएँ होती हैं, अतः 2 × 4 = 8। (4-बिट ring counter में केवल 4 और पूर्ण binary counter में 16 होतीं — यही भ्रम है।)

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