Question
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Answer (Detailed Solution Below)
Option 3 : $50$ kVA; $0.6$ lag / $50$ kVA; $0.6$ पश्च
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Detailed Solution
सही उत्तर $50$ kVA; $0.6$ lag / $50$ kVA; $0.6$ पश्च है।
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prepsnap.in • Part -AQuestion:
A substation auxiliary load draws $P = 30$ kW at $Q = 40$ kVAR (lagging). Using $S = \\sqrt{P^{2}+Q^{2}}$, the apparent power and the power factor are — / एक उपकेंद्र सहायक भार $P = 30$ kW, $Q = 40$ kVAR (पश्चगामी) लेता है। $S = \\sqrt{P^{2}+Q^{2}}$ से आभासी शक्ति तथा शक्ति गुणक हैं —
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$70$ kVA; $0.43$ lag / $70$ kVA; $0.43$ पश्च
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$50$ kVA; $0.8$ lag / $50$ kVA; $0.8$ पश्च
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$50$ kVA; $0.6$ lag / $50$ kVA; $0.6$ पश्च
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$10$ kVA; $3.0$ lag / $10$ kVA; $3.0$ पश्च
Correct Answer: $50$ kVA; $0.6$ lag / $50$ kVA; $0.6$ पश्च
$S = \\sqrt{30^{2}+40^{2}} = \\sqrt{2500} = 50$ kVA; power factor $= P/S = 30/50 = 0.6$ lagging (current lags voltage for an inductive load). / $S = \\sqrt{30^{2}+40^{2}} = \\sqrt{2500} = 50$ kVA; शक्ति गुणक $= P/S = 30/50 = 0.6$ पश्चगामी (प्रेरणिक भार हेतु धारा वोल्टेज से पश्च)।
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