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Answer (Detailed Solution Below)

Option 1 : $600^{\circ}\text{C}$ / $600^{\circ}\text{C}$

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Detailed Solution

सही उत्तर $600^{\circ}\text{C}$ / $600^{\circ}\text{C}$ है।

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PrepSnapprepsnap.in • Part -A

Question:

In a copper–iron thermocouple the neutral temperature is $300^{\circ}\text{C}$ when the cold junction is at $0^{\circ}\text{C}$. The temperature of inversion is / ताँबा–लोहा तापयुग्म में उदासीन ताप $300^{\circ}\text{C}$ है जबकि शीत संधि $0^{\circ}\text{C}$ पर है। व्युत्क्रमण ताप है

1.
$600^{\circ}\text{C}$ / $600^{\circ}\text{C}$
2.
$300^{\circ}\text{C}$ / $300^{\circ}\text{C}$
3.
$150^{\circ}\text{C}$ / $150^{\circ}\text{C}$
4.
$450^{\circ}\text{C}$ / $450^{\circ}\text{C}$

Correct Answer: $600^{\circ}\text{C}$ / $600^{\circ}\text{C}$

The neutral temperature is the mean of the cold-junction and inversion temperatures: $T_n = (T_c + T_i)/2$, so $T_i = 2T_n - T_c = 600 - 0 = 600^{\circ}\text{C}$. / उदासीन ताप शीत संधि और व्युत्क्रमण ताप का माध्य होता है: $T_n = (T_c + T_i)/2$, अतः $T_i = 2T_n - T_c = 600 - 0 = 600^{\circ}\text{C}$।

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