Question
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2.
3.
4.
Answer (Detailed Solution Below)
Option 2 : $30^{\circ}$ / $30^{\circ}$
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Detailed Solution
सही उत्तर $30^{\circ}$ / $30^{\circ}$ है।
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prepsnap.in • Part -AQuestion:
For an equilateral prism the refractive index of the material is $\sqrt{2}$. The angle of minimum deviation is / एक समबाहु प्रिज्म के पदार्थ का अपवर्तनांक $\sqrt{2}$ है। न्यूनतम विचलन का कोण है
1.
$60^{\circ}$ / $60^{\circ}$
2.
$30^{\circ}$ / $30^{\circ}$
3.
$45^{\circ}$ / $45^{\circ}$
4.
$15^{\circ}$ / $15^{\circ}$
Correct Answer: $30^{\circ}$ / $30^{\circ}$
$\mu = \sin[(A + \delta_m)/2]/\sin(A/2)$. With $A = 60^{\circ}$ and $\mu = \sqrt{2}$: $\sin[(60^{\circ} + \delta_m)/2] = \sqrt{2}\sin 30^{\circ} = 1/\sqrt{2} = \sin 45^{\circ}$, giving $\delta_m = 30^{\circ}$. / $\mu = \sin[(A + \delta_m)/2]/\sin(A/2)$। $A = 60^{\circ}$ और $\mu = \sqrt{2}$ रखने पर $\sin[(60^{\circ} + \delta_m)/2] = \sqrt{2}\sin 30^{\circ} = 1/\sqrt{2} = \sin 45^{\circ}$, जिससे $\delta_m = 30^{\circ}$।
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