Question
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Answer (Detailed Solution Below)
Option 4 : 38.7° / 38.7°
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Detailed Solution
सही उत्तर 38.7° / 38.7° है।
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prepsnap.in • Part -AQuestion:
A car moves at $72$ km/h on a banked circular road of radius $50$ m with no lateral friction. Taking $g = 10$ m/s², the required banking angle is / एक कार $72$ km/h चाल से $50$ m त्रिज्या की ढालू वृत्तीय सड़क पर बिना पार्श्व घर्षण के चलती है। $g = 10$ m/s² लेकर, आवश्यक ढलान कोण है
1.
45.0° / 45.0°
2.
84.5° / 84.5°
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21.8° / 21.8°
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38.7° / 38.7°
Correct Answer: 38.7° / 38.7°
$v = 20$ m/s, so $\tan\theta = \dfrac{v^{2}}{rg} = \dfrac{400}{500} = 0.8$ and $\theta = \tan^{-1}(0.8) = 38.7°$. / $v = 20$ m/s, अतः $\tan\theta = \dfrac{v^{2}}{rg} = \dfrac{400}{500} = 0.8$ तथा $\theta = \tan^{-1}(0.8) = 38.7°$।
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