Question

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Answer (Detailed Solution Below)

Option 1 : 4.0 m/s² / 4.0 m/s²

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Detailed Solution

सही उत्तर 4.0 m/s² / 4.0 m/s² है।

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Question:

A $2$ kg block slides down a rough incline of $37°$ with coefficient of kinetic friction $0.25$. Taking $g = 10$ m/s², $\sin 37° = 0.6$ and $\cos 37° = 0.8$, the acceleration of the block is / $2$ kg का गुटका $37°$ के खुरदरे नत समतल पर $0.25$ गतिज घर्षण गुणांक के साथ फिसलता है। $g = 10$ m/s², $\sin 37° = 0.6$ तथा $\cos 37° = 0.8$ लेकर, गुटके का त्वरण है

1.
4.0 m/s² / 4.0 m/s²
2.
6.0 m/s² / 6.0 m/s²
3.
8.0 m/s² / 8.0 m/s²
4.
2.0 m/s² / 2.0 m/s²

Correct Answer: 4.0 m/s² / 4.0 m/s²

$a = g(\sin\theta - \mu\cos\theta) = 10(0.6 - 0.25 \times 0.8) = 10(0.4) = 4.0$ m/s². / $a = g(\sin\theta - \mu\cos\theta) = 10(0.6 - 0.25 \times 0.8) = 10(0.4) = 4.0$ m/s²।

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