Question
1.
2.
3.
4.
Answer (Detailed Solution Below)
Option 1 : 4.0 m/s² / 4.0 m/s²
Advertisement
Detailed Solution
सही उत्तर 4.0 m/s² / 4.0 m/s² है।
Key Points
Helpful?
Question:
A $2$ kg block slides down a rough incline of $37°$ with coefficient of kinetic friction $0.25$. Taking $g = 10$ m/s², $\sin 37° = 0.6$ and $\cos 37° = 0.8$, the acceleration of the block is / $2$ kg का गुटका $37°$ के खुरदरे नत समतल पर $0.25$ गतिज घर्षण गुणांक के साथ फिसलता है। $g = 10$ m/s², $\sin 37° = 0.6$ तथा $\cos 37° = 0.8$ लेकर, गुटके का त्वरण है
1.
4.0 m/s² / 4.0 m/s²
2.
6.0 m/s² / 6.0 m/s²
3.
8.0 m/s² / 8.0 m/s²
4.
2.0 m/s² / 2.0 m/s²
Correct Answer: 4.0 m/s² / 4.0 m/s²
$a = g(\sin\theta - \mu\cos\theta) = 10(0.6 - 0.25 \times 0.8) = 10(0.4) = 4.0$ m/s². / $a = g(\sin\theta - \mu\cos\theta) = 10(0.6 - 0.25 \times 0.8) = 10(0.4) = 4.0$ m/s²।
Downloaded from PrepSnap (prepsnap.in)