Question
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Answer (Detailed Solution Below)
Option 4 : 8.45 m/s / 8.45 m/s
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Detailed Solution
सही उत्तर 8.45 m/s / 8.45 m/s है।
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prepsnap.in • Part -AQuestion:
A solid sphere rolls without slipping down an incline from a vertical height of $5$ m. Taking $g = 10$ m/s², its speed at the bottom is / एक ठोस गोला बिना फिसले नत समतल पर $5$ m ऊर्ध्वाधर ऊँचाई से लुढ़कता है। $g = 10$ m/s² लेकर, तली पर इसकी चाल है
1.
10.00 m/s / 10.00 m/s
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7.07 m/s / 7.07 m/s
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8.16 m/s / 8.16 m/s
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8.45 m/s / 8.45 m/s
Correct Answer: 8.45 m/s / 8.45 m/s
$v = \sqrt{\dfrac{2gh}{1 + I/mr^{2}}} = \sqrt{\dfrac{2(10)(5)}{1 + 2/5}} = \sqrt{\dfrac{100}{1.4}} = 8.45$ m/s. / $v = \sqrt{\dfrac{2gh}{1 + I/mr^{2}}} = \sqrt{\dfrac{2(10)(5)}{1 + 2/5}} = \sqrt{\dfrac{100}{1.4}} = 8.45$ m/s।
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