Question
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Answer (Detailed Solution Below)
Option 1 : $R$ / $R$
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Detailed Solution
सही उत्तर $R$ / $R$ है।
Key Points
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Question:
At what height above Earth's surface does the acceleration due to gravity become $2.5$ m/s², if its surface value is $10$ m/s²? / पृथ्वी की सतह पर गुरुत्वीय त्वरण $10$ m/s² है। सतह से कितनी ऊँचाई पर यह $2.5$ m/s² रह जाता है?
1.
$R$ / $R$
2.
$R/2$ / $R/2$
3.
$R/4$ / $R/4$
4.
$2R$ / $2R$
Correct Answer: $R$ / $R$
$g' = g\left(\dfrac{R}{R+h}\right)^{2} = \dfrac{g}{4}$ gives $\dfrac{R}{R+h} = \dfrac{1}{2}$, so $h = R$. / $g' = g\left(\dfrac{R}{R+h}\right)^{2} = \dfrac{g}{4}$ से $\dfrac{R}{R+h} = \dfrac{1}{2}$, अतः $h = R$।
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