Question

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Answer (Detailed Solution Below)

Option 3 : 4.0 kg·m²/s / 4.0 kg·m²/s

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Detailed Solution

सही उत्तर 4.0 kg·m²/s / 4.0 kg·m²/s है।

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Question:

A particle of mass $0.5$ kg moves at $4$ m/s in a circle of radius $2$ m. Its angular momentum about the centre is / $0.5$ kg का कण $2$ m त्रिज्या के वृत्त में $4$ m/s से गतिमान है। केंद्र के परितः इसका कोणीय संवेग है

1.
2.0 kg·m²/s / 2.0 kg·m²/s
2.
8.0 kg·m²/s / 8.0 kg·m²/s
3.
4.0 kg·m²/s / 4.0 kg·m²/s
4.
1.0 kg·m²/s / 1.0 kg·m²/s

Correct Answer: 4.0 kg·m²/s / 4.0 kg·m²/s

$L = mvr = 0.5 \times 4 \times 2 = 4.0$ kg·m²/s. / $L = mvr = 0.5 \times 4 \times 2 = 4.0$ kg·m²/s।

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