Question
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Answer (Detailed Solution Below)
Option 4 : 2.36 km/s / 2.36 km/s
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Detailed Solution
सही उत्तर 2.36 km/s / 2.36 km/s है।
Key Points
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prepsnap.in • Part -AQuestion:
Taking the Moon's surface gravity as $1.6$ m/s² and its radius as $1.74 \times 10^{6}$ m, the escape velocity from the Moon is / चंद्रमा की सतह पर गुरुत्व $1.6$ m/s² तथा त्रिज्या $1.74 \times 10^{6}$ m लेकर, चंद्रमा से पलायन वेग है
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11.2 km/s / 11.2 km/s
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1.68 km/s / 1.68 km/s
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2.36 m/s / 2.36 m/s
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2.36 km/s / 2.36 km/s
Correct Answer: 2.36 km/s / 2.36 km/s
$v_{e} = \sqrt{2gR} = \sqrt{2(1.6)(1.74 \times 10^{6})} = \sqrt{5.568 \times 10^{6}} = 2.36 \times 10^{3}$ m/s $= 2.36$ km/s. / $v_{e} = \sqrt{2gR} = \sqrt{2(1.6)(1.74 \times 10^{6})} = \sqrt{5.568 \times 10^{6}} = 2.36 \times 10^{3}$ m/s $= 2.36$ km/s।
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