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Answer (Detailed Solution Below)

Option 2 : $2.4\ \mathrm{mm}$ / $2.4\ \mathrm{mm}$

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Detailed Solution

सही उत्तर $2.4\ \mathrm{mm}$ / $2.4\ \mathrm{mm}$ है।

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PrepSnapprepsnap.in • Part -A

Question:

In Young's double-slit experiment, light of wavelength $600\ \mathrm{nm}$ passes through slits $0.5\ \mathrm{mm}$ apart, and the screen is $2\ \mathrm{m}$ away. The fringe width is: / यंग के द्वि-झिरी प्रयोग में $600\ \mathrm{nm}$ तरंगदैर्घ्य का प्रकाश $0.5\ \mathrm{mm}$ अंतराल वाली झिरियों से गुजरता है, और पर्दा $2\ \mathrm{m}$ दूर है। फ्रिंज चौड़ाई है:

1.
$1.2\ \mathrm{mm}$ / $1.2\ \mathrm{mm}$
2.
$2.4\ \mathrm{mm}$ / $2.4\ \mathrm{mm}$
3.
$3.6\ \mathrm{mm}$ / $3.6\ \mathrm{mm}$
4.
$4.8\ \mathrm{mm}$ / $4.8\ \mathrm{mm}$

Correct Answer: $2.4\ \mathrm{mm}$ / $2.4\ \mathrm{mm}$

$\beta = \lambda D/d = (600 \times 10^{-9} \times 2)/(0.5 \times 10^{-3}) = 2.4 \times 10^{-3}\ \mathrm{m} = 2.4\ \mathrm{mm}$. / $\beta = \lambda D/d = (600 \times 10^{-9} \times 2)/(0.5 \times 10^{-3}) = 2.4 \times 10^{-3}\ \mathrm{m} = 2.4\ \mathrm{mm}$।

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