Question
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Answer (Detailed Solution Below)
Option 4 : $0.3\ \mathrm{N}$ / $0.3\ \mathrm{N}$
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Detailed Solution
सही उत्तर $0.3\ \mathrm{N}$ / $0.3\ \mathrm{N}$ है।
Key Points
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prepsnap.in • Part -AQuestion:
A charge of $2\ \mu\mathrm{C}$ moves with velocity $3 \times 10^5\ \mathrm{m/s}$ perpendicular to a uniform magnetic field of $0.5\ \mathrm{T}$. The magnetic force on the charge is: / $2\ \mu\mathrm{C}$ आवेश $0.5\ \mathrm{T}$ के एकसमान चुंबकीय क्षेत्र के लंबवत् $3 \times 10^5\ \mathrm{m/s}$ वेग से गति करता है। आवेश पर चुंबकीय बल है:
1.
$0.03\ \mathrm{N}$ / $0.03\ \mathrm{N}$
2.
$0.06\ \mathrm{N}$ / $0.06\ \mathrm{N}$
3.
$0.15\ \mathrm{N}$ / $0.15\ \mathrm{N}$
4.
$0.3\ \mathrm{N}$ / $0.3\ \mathrm{N}$
Correct Answer: $0.3\ \mathrm{N}$ / $0.3\ \mathrm{N}$
$F = qvB\sin 90^{\circ} = 2 \times 10^{-6} \times 3 \times 10^5 \times 0.5 = 0.3\ \mathrm{N}$. / $F = qvB\sin 90^{\circ} = 2 \times 10^{-6} \times 3 \times 10^5 \times 0.5 = 0.3\ \mathrm{N}$।
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