Question
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Answer (Detailed Solution Below)
Option 4 : $4\,\text{m/s}^2$ / $4\,\text{मी/से}^2$
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Detailed Solution
सही उत्तर $4\,\text{m/s}^2$ / $4\,\text{मी/से}^2$ है।
Key Points
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Question:
A car moves at $72\,\text{km/h}$ around a circular track of radius $100\,\text{m}$. What is its centripetal acceleration? / एक कार $72\,\text{किमी/घंटा}$ की चाल से $100\,\text{मी}$ त्रिज्या के वृत्तीय पथ पर चलती है। इसका अभिकेंद्रीय त्वरण क्या है?
1.
$40\,\text{m/s}^2$ / $40\,\text{मी/से}^2$
2.
$0.4\,\text{m/s}^2$ / $0.4\,\text{मी/से}^2$
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$51.84\,\text{m/s}^2$ / $51.84\,\text{मी/से}^2$
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$4\,\text{m/s}^2$ / $4\,\text{मी/से}^2$
Correct Answer: $4\,\text{m/s}^2$ / $4\,\text{मी/से}^2$
First convert the speed: $72\,\text{km/h} = 20\,\text{m/s}$. Then $a = v^2/r = 400/100 = 4\,\text{m/s}^2$, directed towards the centre. / पहले चाल बदलें: $72\,\text{किमी/घंटा} = 20\,\text{मी/से}$। तब $a = v^2/r = 400/100 = 4\,\text{मी/से}^2$, केंद्र की ओर दिष्ट।
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