Question
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Answer (Detailed Solution Below)
Option 4 : $225\,\text{kJ}$ / $225\,\text{किलोजूल}$
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Detailed Solution
सही उत्तर $225\,\text{kJ}$ / $225\,\text{किलोजूल}$ है।
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prepsnap.in • Part -AQuestion:
A $1500\,\text{kg}$ car accelerates from $10\,\text{m/s}$ to $20\,\text{m/s}$. How much work is done on the car, neglecting losses? / $1500\,\text{किग्रा}$ की एक कार $10\,\text{मी/से}$ से $20\,\text{मी/से}$ तक त्वरित होती है। हानियों को नगण्य मानते हुए, कार पर कितना कार्य किया गया?
1.
$75\,\text{kJ}$ / $75\,\text{किलोजूल}$
2.
$150\,\text{kJ}$ / $150\,\text{किलोजूल}$
3.
$450\,\text{kJ}$ / $450\,\text{किलोजूल}$
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$225\,\text{kJ}$ / $225\,\text{किलोजूल}$
Correct Answer: $225\,\text{kJ}$ / $225\,\text{किलोजूल}$
By the work-energy theorem, $W = \Delta K = \frac{1}{2}m(v^2 - u^2) = \frac{1}{2} \times 1500 \times (400 - 100) = 225000\,\text{J} = 225\,\text{kJ}$. / कार्य-ऊर्जा प्रमेय से, $W = \Delta K = \frac{1}{2}m(v^2 - u^2) = \frac{1}{2} \times 1500 \times (400 - 100) = 225000\,\text{जूल} = 225\,\text{किलोजूल}$।
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