Question
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Answer (Detailed Solution Below)
Option 1 : $1.0\ \text{m}$ / $1.0\ \text{m}$
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Detailed Solution
सही उत्तर $1.0\ \text{m}$ / $1.0\ \text{m}$ है।
Key Points
Helpful?
Question:
A simple pendulum has a time period of $2.0\ \text{s}$. Taking $g = 9.8\ \text{m/s}^2$, its effective length is approximately / एक सरल लोलक का आवर्तकाल $2.0\ \text{s}$ है। $g = 9.8\ \text{m/s}^2$ मानने पर इसकी प्रभावी लंबाई लगभग है
1.
$1.0\ \text{m}$ / $1.0\ \text{m}$
2.
$2.5\ \text{m}$ / $2.5\ \text{m}$
3.
$0.25\ \text{m}$ / $0.25\ \text{m}$
4.
$4.0\ \text{m}$ / $4.0\ \text{m}$
Correct Answer: $1.0\ \text{m}$ / $1.0\ \text{m}$
From $T = 2\pi\sqrt{L/g}$, $L = gT^2/(4\pi^2) = 9.8 \times 4/39.48 \approx 0.99\ \text{m} \approx 1.0\ \text{m}$. / $T = 2\pi\sqrt{L/g}$ से $L = gT^2/(4\pi^2) = 9.8 \times 4/39.48 \approx 0.99\ \text{m} \approx 1.0\ \text{m}$।
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