Question
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Answer (Detailed Solution Below)
Option 2 : $0.80\ \text{s}$ / $0.80\ \text{s}$
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Detailed Solution
सही उत्तर $0.80\ \text{s}$ / $0.80\ \text{s}$ है।
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prepsnap.in • Part -AQuestion:
A concert hall of volume $6000\ \text{m}^3$ has a total sound absorption of $1200$ sabins. Its reverberation time is approximately / $6000\ \text{m}^3$ आयतन वाले एक संगीत सभागार का कुल ध्वनि अवशोषण $1200$ सेबिन है। इसका अनुरणन काल लगभग है
1.
$0.40\ \text{s}$ / $0.40\ \text{s}$
2.
$0.80\ \text{s}$ / $0.80\ \text{s}$
3.
$1.61\ \text{s}$ / $1.61\ \text{s}$
4.
$0.16\ \text{s}$ / $0.16\ \text{s}$
Correct Answer: $0.80\ \text{s}$ / $0.80\ \text{s}$
Sabine's formula gives $T = 0.161V/A = 0.161 \times 6000/1200 \approx 0.80\ \text{s}$. / सेबिन सूत्र से $T = 0.161V/A = 0.161 \times 6000/1200 \approx 0.80\ \text{s}$।
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