Question
1.
2.
3.
4.
Answer (Detailed Solution Below)
Option 1 : $0.54$ / $0.54$
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Detailed Solution
सही उत्तर $0.54$ / $0.54$ है।
Key Points
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Question:
An optical fibre has core index $1.5$ and cladding index $1.4$. Its numerical aperture is approximately / एक प्रकाशिक तंतु के क्रोड का अपवर्तनांक $1.5$ तथा अधिपट्ट का $1.4$ है। इसका संख्यात्मक द्वारक लगभग है
1.
$0.54$ / $0.54$
2.
$0.29$ / $0.29$
3.
$2.05$ / $2.05$
4.
$0.10$ / $0.10$
Correct Answer: $0.54$ / $0.54$
$NA = \sqrt{n_1^2 - n_2^2} = \sqrt{1.5^2 - 1.4^2} = \sqrt{0.29} \approx 0.54$. / $NA = \sqrt{n_1^2 - n_2^2} = \sqrt{1.5^2 - 1.4^2} = \sqrt{0.29} \approx 0.54$।
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