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Question

1.
2.
3.
4.
Answer (Detailed Solution Below)

Option 4 : $0.125I_0$ / $0.125I_0$

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Detailed Solution

सही उत्तर $0.125I_0$ / $0.125I_0$ है।

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PrepSnapprepsnap.in • Part -A

Question:

Unpolarised light of intensity $I_0$ passes through a polariser and then an analyser whose transmission axis makes $60^\circ$ with the polariser. The emergent intensity is / $I_0$ तीव्रता का अध्रुवित प्रकाश एक ध्रुवक से गुजरता है, फिर एक विश्लेषक से जिसका पारगमन अक्ष ध्रुवक से $60^\circ$ बनाता है। निर्गत तीव्रता है

1.
$0.50I_0$ / $0.50I_0$
2.
$0.25I_0$ / $0.25I_0$
3.
$I_0$ / $I_0$
4.
$0.125I_0$ / $0.125I_0$

Correct Answer: $0.125I_0$ / $0.125I_0$

By Malus' law, $I = (I_0/2)\cos^2 60^\circ = (I_0/2)(1/4) = I_0/8 = 0.125I_0$. / मैलस नियम से $I = (I_0/2)\cos^2 60^\circ = (I_0/2)(1/4) = I_0/8 = 0.125I_0$।

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