Question
1.
2.
3.
4.
Answer (Detailed Solution Below)
Option 3 : $80$ / $80$
Advertisement
Detailed Solution
सही उत्तर $80$ / $80$ है।
Key Points
Helpful?
prepsnap.in • Part -AQuestion:
A compound microscope has an objective of focal length $1.0\ \text{cm}$, tube length $16\ \text{cm}$, and an eyepiece of focal length $5.0\ \text{cm}$ (near point $25\ \text{cm}$). Its total magnification is / एक संयुक्त सूक्ष्मदर्शी के अभिदृश्यक की फोकस दूरी $1.0\ \text{cm}$, नली की लंबाई $16\ \text{cm}$ तथा नेत्रिका की फोकस दूरी $5.0\ \text{cm}$ है (निकट बिंदु $25\ \text{cm}$)। इसका कुल आवर्धन है
1.
$40$ / $40$
2.
$160$ / $160$
3.
$80$ / $80$
4.
$25$ / $25$
Correct Answer: $80$ / $80$
$M = (L/f_o)(D/f_e) = (16/1.0)(25/5.0) = 16 \times 5 = 80$. / $M = (L/f_o)(D/f_e) = (16/1.0)(25/5.0) = 16 \times 5 = 80$।
Downloaded from PrepSnap (prepsnap.in)