Question

Answer (Detailed Solution Below)

Option 2 : $2.8 \times 10^{-7}\ \text{rad}$ / $2.8 \times 10^{-7}\ \text{rad}$

Detailed Solution

सही उत्तर $2.8 \times 10^{-7}\ \text{rad}$ / $2.8 \times 10^{-7}\ \text{rad}$ है।

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prepsnap.in • Part -A

Question:

A telescope of aperture $2.4\ \text{m}$ observes at $\lambda = 550\ \text{nm}$. Its Rayleigh angular resolution is approximately / $2.4\ \text{m}$ द्वारक वाली एक दूरबीन $\lambda = 550\ \text{nm}$ पर प्रेक्षण करती है। इसका रेले कोणीय विभेदन लगभग है

$2.8 \times 10^{-6}\ \text{rad}$ / $2.8 \times 10^{-6}\ \text{rad}$

$2.8 \times 10^{-7}\ \text{rad}$ / $2.8 \times 10^{-7}\ \text{rad}$

$2.3 \times 10^{-7}\ \text{rad}$ / $2.3 \times 10^{-7}\ \text{rad}$

$1.4 \times 10^{-7}\ \text{rad}$ / $1.4 \times 10^{-7}\ \text{rad}$

Correct Answer: $2.8 \times 10^{-7}\ \text{rad}$ / $2.8 \times 10^{-7}\ \text{rad}$

$\theta = 1.22\lambda/D = 1.22 \times 550 \times 10^{-9}/2.4 \approx 2.8 \times 10^{-7}\ \text{rad}$. / $\theta = 1.22\lambda/D = 1.22 \times 550 \times 10^{-9}/2.4 \approx 2.8 \times 10^{-7}\ \text{rad}$।

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