Question
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Answer (Detailed Solution Below)
Option 1 : $20\ \text{rad/s}$ / $20\ \text{rad/s}$
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Detailed Solution
सही उत्तर $20\ \text{rad/s}$ / $20\ \text{rad/s}$ है।
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prepsnap.in • Part -AQuestion:
A particle in SHM has maximum acceleration $20\ \text{m/s}^2$ and amplitude $0.05\ \text{m}$. Its angular frequency is / सरल आवर्त गति करता एक कण अधिकतम त्वरण $20\ \text{m/s}^2$ तथा आयाम $0.05\ \text{m}$ रखता है। इसकी कोणीय आवृत्ति है
1.
$20\ \text{rad/s}$ / $20\ \text{rad/s}$
2.
$10\ \text{rad/s}$ / $10\ \text{rad/s}$
3.
$40\ \text{rad/s}$ / $40\ \text{rad/s}$
4.
$400\ \text{rad/s}$ / $400\ \text{rad/s}$
Correct Answer: $20\ \text{rad/s}$ / $20\ \text{rad/s}$
From $a_{max} = \omega^2 A$, $\omega = \sqrt{20/0.05} = \sqrt{400} = 20\ \text{rad/s}$. / $a_{max} = \omega^2 A$ से $\omega = \sqrt{20/0.05} = \sqrt{400} = 20\ \text{rad/s}$।
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