Question

1.
2.
3.
4.
Answer (Detailed Solution Below)

Option 4 : 1/4 / 1/4

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Detailed Solution

सही उत्तर 1/4 / 1/4 है।

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Question:

According to the $\cos^4$ law, illumination at a point 45 degrees off the lens axis falls to what fraction of the centre value? / $\cos^4$ नियम के अनुसार, लेंस अक्ष से 45 डिग्री दूर किसी बिंदु पर प्रकाश केंद्र मान के कितने भाग तक गिरता है?

1.
1/2 / 1/2
2.
$1/\sqrt{2}$ / $1/\sqrt{2}$
3.
3/4 / 3/4
4.
1/4 / 1/4

Correct Answer: 1/4 / 1/4

Falloff equals $\cos^4\theta$; at $45^\circ$, $\cos 45^\circ = \sqrt{2}/2$, and $(\sqrt{2}/2)^4 = 1/4$, so edges receive one-quarter of the central illumination (two stops down).

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