Question
1.
2.
3.
4.
Answer (Detailed Solution Below)
Option 3 : +0.059 V
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Detailed Solution
सही उत्तर +0.059 V है।
Key Points
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prepsnap.in • Part -AQuestion:
For the concentration cell Ag|Ag+(0.010 M)||Ag+(0.10 M)|Ag at 25 C, the cell EMF is / 25 C पर सांद्रता सेल Ag|Ag+(0.010 M)||Ag+(0.10 M)|Ag का EMF है
1.
0 V
2.
-0.059 V
3.
+0.059 V
4.
+0.118 V
Correct Answer: +0.059 V
$E = \frac{0.0591}{1}\log\frac{0.10}{0.010} = +0.059$ V; the cathode is the more concentrated half-cell, so the sign is positive. / $E = \frac{0.0591}{1}\log\frac{0.10}{0.010} = +0.059$ V; कैथोड अधिक सांद्र अर्ध-सेल है, अतः चिह्न धनात्मक है।
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