Question
1.
2.
3.
4.
Answer (Detailed Solution Below)
Option 2 : $1.23$ Å / $1.23$ Å
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Detailed Solution
सही उत्तर $1.23$ Å / $1.23$ Å है।
Key Points
Helpful?
Question:
An electron is accelerated through a potential difference of $100$ V. Its de Broglie wavelength is closest to / एक इलेक्ट्रॉन को $100$ V विभवांतर से त्वरित किया गया। इसकी डी-ब्रॉग्ली तरंगदैर्घ्य निकटतम है
1.
$12.26$ Å / $12.26$ Å
2.
$1.23$ Å / $1.23$ Å
3.
$0.123$ Å / $0.123$ Å
4.
$0.0123$ Å / $0.0123$ Å
Correct Answer: $1.23$ Å / $1.23$ Å
$\lambda = h/\sqrt{2m_e eV} = 12.26/\sqrt{100}$ Å $= 1.23$ Å. / $\lambda = h/\sqrt{2m_e eV} = 12.26/\sqrt{100}$ Å $= 1.23$ Å।
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