Question

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2.
3.
4.
Answer (Detailed Solution Below)

Option 4 : 60,000 / 60,000

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Detailed Solution

सही उत्तर 60,000 / 60,000 है।

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Question:

The population of a town increases by $10\%$ every year. If its present population is $72,600$, what was the population 2 years ago? / एक नगर की जनसंख्या प्रतिवर्ष $10\%$ बढ़ती है। यदि वर्तमान जनसंख्या $72,600$ है, तो 2 वर्ष पूर्व जनसंख्या कितनी थी?

1.
66,000 / 66,000
2.
59,400 / 59,400
3.
65,000 / 65,000
4.
60,000 / 60,000

Correct Answer: 60,000 / 60,000

Let the population 2 years ago be $P$. Then $P \times 1.1 \times 1.1 = 72600$, so $P = \frac{72600}{1.21} = 60000$. Simply subtracting $20\%$ gives the wrong answer. / माना 2 वर्ष पूर्व जनसंख्या $P$ थी। तब $P \times 1.1 \times 1.1 = 72600$, अतः $P = \frac{72600}{1.21} = 60000$। सीधे $20\%$ घटाने पर गलत उत्तर मिलेगा।

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