Question
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Answer (Detailed Solution Below)
Option 2 : 48 / 48
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Detailed Solution
सही उत्तर 48 / 48 है।
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prepsnap.in • Part -AQuestion:
If $x$ is the fourth proportional to 3, 9 and 12, and $y$ is the mean proportional between 4 and 36, find $x + y$. / यदि $x$, 3, 9 और 12 का चतुर्थ समानुपाती है तथा $y$, 4 और 36 का मध्य समानुपाती है, तो $x + y$ ज्ञात कीजिए।
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42 / 42
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48 / 48
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54 / 54
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60 / 60
Correct Answer: 48 / 48
$x = \frac{9 \times 12}{3} = 36$; $y = \sqrt{4 \times 36} = 12$; $x + y = 48$. / $x = \frac{9 \times 12}{3} = 36$; $y = \sqrt{4 \times 36} = 12$; $x + y = 48$।
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